g^2+19g=72

Solution for g^2+19g=72 equation:

g^2+19g=72

We move all terms to the left:

g^2+19g-(72)=0

a = 1; b = 19; c = -72;
Δ = b2-4ac
Δ = 192-4·1·(-72)
Δ = 649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{649}}{2*1}=\frac{-19-\sqrt{649}}{2}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{649}}{2*1}=\frac{-19+\sqrt{649}}{2}
$